Optimal. Leaf size=67 \[ \frac {a^2 \tanh ^{-1}(\sin (c+d x))}{d}+\frac {2 a b \sec (c+d x)}{d}-\frac {b^2 \tanh ^{-1}(\sin (c+d x))}{2 d}+\frac {b^2 \tan (c+d x) \sec (c+d x)}{2 d} \]
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Rubi [A] time = 0.09, antiderivative size = 67, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 5, integrand size = 28, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.179, Rules used = {3090, 3770, 2606, 8, 2611} \[ \frac {a^2 \tanh ^{-1}(\sin (c+d x))}{d}+\frac {2 a b \sec (c+d x)}{d}-\frac {b^2 \tanh ^{-1}(\sin (c+d x))}{2 d}+\frac {b^2 \tan (c+d x) \sec (c+d x)}{2 d} \]
Antiderivative was successfully verified.
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Rule 8
Rule 2606
Rule 2611
Rule 3090
Rule 3770
Rubi steps
\begin {align*} \int \sec ^3(c+d x) (a \cos (c+d x)+b \sin (c+d x))^2 \, dx &=\int \left (a^2 \sec (c+d x)+2 a b \sec (c+d x) \tan (c+d x)+b^2 \sec (c+d x) \tan ^2(c+d x)\right ) \, dx\\ &=a^2 \int \sec (c+d x) \, dx+(2 a b) \int \sec (c+d x) \tan (c+d x) \, dx+b^2 \int \sec (c+d x) \tan ^2(c+d x) \, dx\\ &=\frac {a^2 \tanh ^{-1}(\sin (c+d x))}{d}+\frac {b^2 \sec (c+d x) \tan (c+d x)}{2 d}-\frac {1}{2} b^2 \int \sec (c+d x) \, dx+\frac {(2 a b) \operatorname {Subst}(\int 1 \, dx,x,\sec (c+d x))}{d}\\ &=\frac {a^2 \tanh ^{-1}(\sin (c+d x))}{d}-\frac {b^2 \tanh ^{-1}(\sin (c+d x))}{2 d}+\frac {2 a b \sec (c+d x)}{d}+\frac {b^2 \sec (c+d x) \tan (c+d x)}{2 d}\\ \end {align*}
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Mathematica [A] time = 0.04, size = 67, normalized size = 1.00 \[ \frac {a^2 \tanh ^{-1}(\sin (c+d x))}{d}+\frac {2 a b \sec (c+d x)}{d}-\frac {b^2 \tanh ^{-1}(\sin (c+d x))}{2 d}+\frac {b^2 \tan (c+d x) \sec (c+d x)}{2 d} \]
Antiderivative was successfully verified.
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fricas [A] time = 0.69, size = 96, normalized size = 1.43 \[ \frac {{\left (2 \, a^{2} - b^{2}\right )} \cos \left (d x + c\right )^{2} \log \left (\sin \left (d x + c\right ) + 1\right ) - {\left (2 \, a^{2} - b^{2}\right )} \cos \left (d x + c\right )^{2} \log \left (-\sin \left (d x + c\right ) + 1\right ) + 8 \, a b \cos \left (d x + c\right ) + 2 \, b^{2} \sin \left (d x + c\right )}{4 \, d \cos \left (d x + c\right )^{2}} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [A] time = 4.74, size = 122, normalized size = 1.82 \[ \frac {{\left (2 \, a^{2} - b^{2}\right )} \log \left ({\left | \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 1 \right |}\right ) - {\left (2 \, a^{2} - b^{2}\right )} \log \left ({\left | \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - 1 \right |}\right ) + \frac {2 \, {\left (b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} - 4 \, a b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} + b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 4 \, a b\right )}}{{\left (\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} - 1\right )}^{2}}}{2 \, d} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 1.69, size = 98, normalized size = 1.46 \[ \frac {a^{2} \ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{d}+\frac {2 a b}{d \cos \left (d x +c \right )}+\frac {b^{2} \left (\sin ^{3}\left (d x +c \right )\right )}{2 d \cos \left (d x +c \right )^{2}}+\frac {b^{2} \sin \left (d x +c \right )}{2 d}-\frac {b^{2} \ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{2 d} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [A] time = 0.33, size = 89, normalized size = 1.33 \[ -\frac {b^{2} {\left (\frac {2 \, \sin \left (d x + c\right )}{\sin \left (d x + c\right )^{2} - 1} + \log \left (\sin \left (d x + c\right ) + 1\right ) - \log \left (\sin \left (d x + c\right ) - 1\right )\right )} - 2 \, a^{2} {\left (\log \left (\sin \left (d x + c\right ) + 1\right ) - \log \left (\sin \left (d x + c\right ) - 1\right )\right )} - \frac {8 \, a b}{\cos \left (d x + c\right )}}{4 \, d} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 0.90, size = 106, normalized size = 1.58 \[ \frac {b^2\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^3+b^2\,\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )-4\,a\,b\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2+4\,a\,b}{d\,\left ({\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^4-2\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2+1\right )}+\frac {\mathrm {atanh}\left (\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )\right )\,\left (2\,a^2-b^2\right )}{d} \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \left (a \cos {\left (c + d x \right )} + b \sin {\left (c + d x \right )}\right )^{2} \sec ^{3}{\left (c + d x \right )}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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